Integrand size = 18, antiderivative size = 67 \[ \int \frac {A+B x}{x (a+b x)^{5/2}} \, dx=\frac {2 (A b-a B)}{3 a b (a+b x)^{3/2}}+\frac {2 A}{a^2 \sqrt {a+b x}}-\frac {2 A \text {arctanh}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{a^{5/2}} \]
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Time = 0.01 (sec) , antiderivative size = 67, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.222, Rules used = {79, 53, 65, 214} \[ \int \frac {A+B x}{x (a+b x)^{5/2}} \, dx=-\frac {2 A \text {arctanh}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{a^{5/2}}+\frac {2 A}{a^2 \sqrt {a+b x}}+\frac {2 (A b-a B)}{3 a b (a+b x)^{3/2}} \]
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Rule 53
Rule 65
Rule 79
Rule 214
Rubi steps \begin{align*} \text {integral}& = \frac {2 (A b-a B)}{3 a b (a+b x)^{3/2}}+\frac {A \int \frac {1}{x (a+b x)^{3/2}} \, dx}{a} \\ & = \frac {2 (A b-a B)}{3 a b (a+b x)^{3/2}}+\frac {2 A}{a^2 \sqrt {a+b x}}+\frac {A \int \frac {1}{x \sqrt {a+b x}} \, dx}{a^2} \\ & = \frac {2 (A b-a B)}{3 a b (a+b x)^{3/2}}+\frac {2 A}{a^2 \sqrt {a+b x}}+\frac {(2 A) \text {Subst}\left (\int \frac {1}{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b x}\right )}{a^2 b} \\ & = \frac {2 (A b-a B)}{3 a b (a+b x)^{3/2}}+\frac {2 A}{a^2 \sqrt {a+b x}}-\frac {2 A \tanh ^{-1}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{a^{5/2}} \\ \end{align*}
Time = 0.09 (sec) , antiderivative size = 64, normalized size of antiderivative = 0.96 \[ \int \frac {A+B x}{x (a+b x)^{5/2}} \, dx=-\frac {2 \left (-a A b+a^2 B-3 A b (a+b x)\right )}{3 a^2 b (a+b x)^{3/2}}-\frac {2 A \text {arctanh}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{a^{5/2}} \]
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Time = 1.80 (sec) , antiderivative size = 59, normalized size of antiderivative = 0.88
method | result | size |
derivativedivides | \(\frac {-\frac {2 \left (-A b +B a \right )}{3 a \left (b x +a \right )^{\frac {3}{2}}}+\frac {2 A b}{a^{2} \sqrt {b x +a}}-\frac {2 A b \,\operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{a^{\frac {5}{2}}}}{b}\) | \(59\) |
default | \(\frac {-\frac {2 \left (-A b +B a \right )}{3 a \left (b x +a \right )^{\frac {3}{2}}}+\frac {2 A b}{a^{2} \sqrt {b x +a}}-\frac {2 A b \,\operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{a^{\frac {5}{2}}}}{b}\) | \(59\) |
pseudoelliptic | \(-\frac {2 \left (3 A \left (b x +a \right )^{\frac {3}{2}} b \,\operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )-3 A \sqrt {a}\, b^{2} x -4 A \,a^{\frac {3}{2}} b +B \,a^{\frac {5}{2}}\right )}{3 \left (b x +a \right )^{\frac {3}{2}} a^{\frac {5}{2}} b}\) | \(62\) |
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Time = 0.24 (sec) , antiderivative size = 221, normalized size of antiderivative = 3.30 \[ \int \frac {A+B x}{x (a+b x)^{5/2}} \, dx=\left [\frac {3 \, {\left (A b^{3} x^{2} + 2 \, A a b^{2} x + A a^{2} b\right )} \sqrt {a} \log \left (\frac {b x - 2 \, \sqrt {b x + a} \sqrt {a} + 2 \, a}{x}\right ) + 2 \, {\left (3 \, A a b^{2} x - B a^{3} + 4 \, A a^{2} b\right )} \sqrt {b x + a}}{3 \, {\left (a^{3} b^{3} x^{2} + 2 \, a^{4} b^{2} x + a^{5} b\right )}}, \frac {2 \, {\left (3 \, {\left (A b^{3} x^{2} + 2 \, A a b^{2} x + A a^{2} b\right )} \sqrt {-a} \arctan \left (\frac {\sqrt {b x + a} \sqrt {-a}}{a}\right ) + {\left (3 \, A a b^{2} x - B a^{3} + 4 \, A a^{2} b\right )} \sqrt {b x + a}\right )}}{3 \, {\left (a^{3} b^{3} x^{2} + 2 \, a^{4} b^{2} x + a^{5} b\right )}}\right ] \]
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Time = 2.07 (sec) , antiderivative size = 83, normalized size of antiderivative = 1.24 \[ \int \frac {A+B x}{x (a+b x)^{5/2}} \, dx=\begin {cases} \frac {2 A}{a^{2} \sqrt {a + b x}} + \frac {2 A \operatorname {atan}{\left (\frac {\sqrt {a + b x}}{\sqrt {- a}} \right )}}{a^{2} \sqrt {- a}} - \frac {2 \left (- A b + B a\right )}{3 a b \left (a + b x\right )^{\frac {3}{2}}} & \text {for}\: b \neq 0 \\\frac {A \log {\left (B x \right )} + B x}{a^{\frac {5}{2}}} & \text {otherwise} \end {cases} \]
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Time = 0.30 (sec) , antiderivative size = 69, normalized size of antiderivative = 1.03 \[ \int \frac {A+B x}{x (a+b x)^{5/2}} \, dx=\frac {A \log \left (\frac {\sqrt {b x + a} - \sqrt {a}}{\sqrt {b x + a} + \sqrt {a}}\right )}{a^{\frac {5}{2}}} - \frac {2 \, {\left (B a^{2} - 3 \, {\left (b x + a\right )} A b - A a b\right )}}{3 \, {\left (b x + a\right )}^{\frac {3}{2}} a^{2} b} \]
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Time = 0.30 (sec) , antiderivative size = 61, normalized size of antiderivative = 0.91 \[ \int \frac {A+B x}{x (a+b x)^{5/2}} \, dx=\frac {2 \, A \arctan \left (\frac {\sqrt {b x + a}}{\sqrt {-a}}\right )}{\sqrt {-a} a^{2}} - \frac {2 \, {\left (B a^{2} - 3 \, {\left (b x + a\right )} A b - A a b\right )}}{3 \, {\left (b x + a\right )}^{\frac {3}{2}} a^{2} b} \]
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Time = 0.57 (sec) , antiderivative size = 56, normalized size of antiderivative = 0.84 \[ \int \frac {A+B x}{x (a+b x)^{5/2}} \, dx=\frac {\frac {2\,\left (A\,b-B\,a\right )}{3\,a}+\frac {2\,A\,b\,\left (a+b\,x\right )}{a^2}}{b\,{\left (a+b\,x\right )}^{3/2}}-\frac {2\,A\,\mathrm {atanh}\left (\frac {\sqrt {a+b\,x}}{\sqrt {a}}\right )}{a^{5/2}} \]
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